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Entity Framework

EntityGraphQL is built to work extremely well with EntityFramework. To see how let's first look at what EntityGraphQL does with GraphQL queries.

Examples

Using the DemoContext and the schema we created from the Getting Started section, lets look at the sample queries.

query {
movie(id: 11) {
id
name
}
}

EntityGraphQL parses the GQL document into an internal representation and uses the schema we built to construct a .NET expression. It will look like this.

var expression = (DemoContext ctx, AnonymousType<> args) =>
ctx.Movies
.Where(movie => movie.Id == args.id)
.Select(movie => new {
id = movie.Id,
name = movie.Name
})
.FirstOrDefault();

You can see all we need to execute this expression is an instance of DemoContext and the args object which is built by EntityGraphQL on parsing of the GQL document. Given those things EntityGraphQL can do similar to this.

var results = expression.Compile().DynamicInvoke(demoContextInstance, argInstance);

Now if your DemoContext is built on top of Entity Framework DbContext when EntityGraphQL executes the expression EF will take over and do its thing!

Namely note that EntityGraphQL only selects the fields asked for and therefore EF will also only return the fields we ask for. Meaning no over fetching to the DB either. If your table had many fields and some large ones, they are not selected from the DB unless the API user asks for those fields.

Let's look at a more complicated example.

{
movies {
id
name
director {
name
}
writers {
name
}
}
}

Will result in the following expression.

var expression = (DemoContext ctx) =>
ctx.Movies
.Select(movie => new {
id = movie.Id,
name = movie.Name,
director = new {
name = movie.Director.Name
},
writers = movie.Writers.Select(writer => new {
name = writer.Name
})
});

Again, EF will take over and fetch your data for you.

You'll note that EntityGraphQL doesn't care what the context is. It could be a object graph 100% held in memory. What does matter is that when the expression executes and resolves something like movie.Writers.Select() that the object has the expected data loaded, or like EF can resolve the data.

Other ORMs built on top of LinqProvider and IQueryable should also work although have not been tested.

How EntityGraphQL handles services / Resolve<TService>()

Since using EntityGraphQL against an Entity Framework Core DbContext is supported we handle Resolve<TService>() in a way that will work with EF Core (and possibly other IQueryable based ORMs) which allows EF to build an optimal SQL statement. EF core 3.1+ will throw an error by default if it can't translate an expression to SQL. It can't translate the services used in Resolve<TService>() to SQL. To support EF 3.1+ performing optimal queries (and selecting only the fields you request) EntityGraphQL builds and executes the expressions in 2 parts.

This can be disabled by setting the argument ExecuteServiceFieldsSeparately when executing to false. For example if your core context is an in memory object.

If you encounter any issues when using Resolve<TService>() on fields and EF Core 3.1+ please raise an issue.

Example of how EntityGraphQL handles Resolve<TService>(), which can help inform how you build/use other services.

Given the following GQL

{
people {
age
manager {
name
}
}
}

Where age is defined with a service as

schema.Type<Person>().AddField("age", "Persons age")
.Resolve<AgeService>((person, ager) => ager.GetAge(person.Birthday));

EntityGraphQL will build an expression query that first selects everything from the base context (DemoContext in this case) that EF can execute. Then another expression query that runs on top of that result which includes the Resolve<TService>() fields. This means EF can optimize your query and return all the data requested (and nothing more) and in memory we then merge that with data from your services.

An example in C# of what this ends up looking like.

var dbResultFunc = (DbContext context) => context.People.Select(p => new {
p_Birthday = p.Birthday, // extracted from the Resolve<TService> expression as it is needed in the in-memory resolution
manager = new {
name = p.Manager.Name
}
})
.ToList(); // EF will fetch data
var dbResult = dbResultFunc(dbContext); // executes the expression

// note dbResult is an anonymous type known at runtime
var resultsFunc = (AnonType dbResult, AgeService ager) => dbResult.Select(p => {
age = ager.GetAge(p.p_Birthday), // passing in data we selected just for this
manager = p.manager // simple selection from the previous result
})
.ToList();
var results = resultsFunc(dbResult, ager); // execute for the final result

This allows EF Core to make its optimizations and prevent over-fetching of data when using EntityGraphQL against an EF DbContext.

As seen above EntityGraphQL will execute 2 expressions. The first with all data on the main query context (in this case the DbContext) without the service fields and the second against the result of that query including the service fields.

To do this EntityGraphQL needs to update the service field expressions. It does that by first extracting all the expressions form a service that relate to the main query context. For example

schema.UpdateType<Floor>(type => {
type.AddField("floorUrl", "Current floor url")
.Resolve<IFloorUrlService>((floor, srv) => s.BuildFloorPlanUrl(f.SomeRelation.FirstOrDefault().Id));
});

Will extract the f.SomeRelation.FirstOrDefault().Id expression. That will be fetched in the first expression execution as f.SomeRelation_FirstOrDefault___Id = f.SomeRelation.FirstOrDefault().Id. So when we rebuild the final expression to also execute service fields it will update the expression to be s.BuildFloorPlanUrl(f.SomeRelation_FirstOrDefault___Id).

You may encounter some issues with EF depending on how complex you expressions are. For example pre-6.0 this issue will be hit if you traverse through a relation.

It is best to keep the expressions used to pass query context data into a service as simple as you can. Remember, your services can also access the DB context or anything else they need via DI.